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def my_function(an_int: int): return an_int * 2 print(my_function("Python"))
Even though the function parameter type is annotated (the function is expecting to receive an int ), it doesn't mean that the argument has to be of this type. (python.org/dev/peps/pep-0484)
What is the output of the code snippet below?— The Python Quiz (@thepythonquiz) June 23, 2021
def my_function(an_int: int):
return an_int * 2
It will throw a SyntaxError exception.
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