The Python Quiz | What is the output of the code snippet below? class Foo(object): def __init__(self): self.__method() def __method(self): print('42') class MoreFoo(Foo): def _

This is a question page. You can use this page to bookmark a question. Start a new quiz!

Question #545

What is the output of the code snippet below?

class Foo(object):
    def __init__(self):
        self.__method()
    def __method(self):
        print('42')

class MoreFoo(Foo):
    def __method(self):
        print('41')

MoreFoo()

As __method() is a private method (recognisable by the double underscores __ ), it cannot be overridden by simply defining it as __method(self) in the subclass (to avoid accidental override). To force overridding, it has to be redefined as def _Foo__method(self): . This is called name mangling. (stackoverflow.com/questions/14898197/override-private-met...)

Comment on Disqus:

Question difficulty: 🔵🔵🔵🔵🔵