Question #350

What is the output of the code snippet below?
def func1():
    return 10

def func2():
    return func1()

def func3():
    return func2() * 5

print(func3())

Here, fun3() is invoked first. The code will start from fun3() that will invoke fun2(). Finally, fun2() will invoke fun1() , multiply 10 by 5 and return 50 . (tutorialspoint.com/python/python_functions.htm)


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