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Question #350
def func1():
return 10
def func2():
return func1()
def func3():
return func2() * 5
print(func3())
Here, fun3() is invoked first. The code will start from fun3() that will invoke fun2(). Finally, fun2() will invoke fun1() , multiply 10 by 5 and return 50 . (tutorialspoint.com/python/python_functions.htm)
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