Question #131

What is the output of the code snippet below?
import copy
a = [[1], [2]]
b = copy.copy(a)
print(a[0] is b[0])

When copy.copy() is used (shallow copy), the copy of the object has a new memory address but its elements refer to the elements of the copied object. Here, a[0] and b[0] are the same object with the same memory address. (towardsdatascience.com/assignment-shallow-or-deep-a-story...)


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